Spread Knowledge

CS606 - Compiler Construction - Lecture Handout 37

User Rating:  / 0
PoorBest 

Related Content: CS606 - VU Lectures, Handouts, PPT Slides, Assignments, Quizzes, Papers & Books of Compiler Construction

Here is the bottom-up parse of the assignment statement a = b*-c + b*-c and the syntax-directed translation into three-address code.

Parser action attribute Three- address code
id=id ∗ –id + id ∗ –id    
id=E1 ∗ –id + id ∗ –id E1.place = b  
id=E1 ∗ –E2 + id ∗ –id E2.place = c  
id=E1 ∗ E2 + id ∗ –id E2.place = t1 t1 = – c
id=E1 + id ∗ –id E1.place = t2 t2 = b∗t1
id=E1 + E2 ∗ –id E2.place = b  
id=E1 + E2 ∗ –E3 E3.place = c  
id=E1 + E2 ∗ E3 E3.place = t3 t3 = – c
id=E1 + E2 E2.place = t4 t4 = b∗t3
id=E1 E1.place = t5 t5 = t2+t4
S   a = t5

Representing Linear Codes

Three-address codes are often implemented as a set of quadruples. Each quadruple has four fields: an operator, two operands (or sources) and a destination. In C++, for example, one can design a quadruple class and then declare a simple array of quadruples.
This leads to the following arrangement; the index of the array element acts as the number of quadruple generated.

Target Op Arg1 Arg2
t1 2  
t2 y  
t3 × t1 t2
t4 x  
t5 t4 t3

An array of pointers to quads can be employed which leads to the following structure:

pointers to quads

Flow-of-Control Statements

We now use the syntax-directed translation scheme for the flow-of-control statements found in most procedural programming languages.

Flow-of-Control Statements

where E is a boolean expression. Consider the statement

if c < d then
x = y + z
else
x = y – z

One possible 3-address code could be

if c < d goto L1
goto L2
L1: x = y + z
goto L3
L2: x = y – z
L3: nop

We will assume that a three-address statement can be symbolically labeled;
the function newlabel() returns a new symbolic label each time it is called